What will be remainder when (6767 + 67) is divided by 68 ?

Answer: Option C

Explanation:

(x^{n} + 1) will be divisible by (x + 1) only when n is odd.

(67^{67} + 1) will be divisible by (67 + 1)

(67^{67} + 1) + 66, when divided by 68 will give 66 as remainder.