1. | An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is: |
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Answer: Option A Explanation: Let AB be the observer and CD be the tower. Draw BE CD. Then, CE = AB = 1.6 m, BE = AC = 203 m.
CD = CE + DE = (1.6 + 20) m = 21.6 m. |

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